Cricket Web Maths help.

 23-04-2009, 07:45 AM #1 (permalink) International Captain     Join Date: Dec 2006 Location: Liverpool, England Posts: 7,049 Maths help. I always get stuck on these type of equations, could anyone find me an easy way to work them out. The equations; 5x-2=x+10 5x-2=3x+1 3(x+4)=x-5 5(x-2)=2(x+4) Shameful I know, but I have my reasons. __________________ Everyone wants to change the world, noone wants to change himself. -Tolstoy
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dude, these are way too simple.

move all X's to one side of the equation and all loose terms to the other, and bingo.

for instance, the first one:

5x - 2 = x + 10
5x -x = 10 + 2
4x = 12
x = 3
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 23-04-2009, 07:52 AM #3 (permalink) International Captain     Join Date: Dec 2006 Location: Liverpool, England Posts: 7,049 Also this simultaneous equation: 5x+3y=8 3x-y=9 I know this is pathetic but still.
 23-04-2009, 07:52 AM #4 (permalink) Eternal Optimist     Join Date: Dec 2005 Location: Shake my tree where's the apple for me? Posts: 43,601 5x=x+8 5x=3x+3 3x+7=x 5x=2x+18 I have done some quick cancelling out for you that may well be wrong as I am only on a quick break. Let me know if that helps, it should make things a bit simpler. basically the first thing you need to do is balance the equation. If you have something saying x+ 7= 3x+19, take 7 off both, ie x=3x+12. Thinking about it now it seems a ridiculously bad example, but hopefully you see what I mean All this being said, there are plenty of maths geeks here better than me __________________ Watch out, for as soon as it pleases them they’ll send you out to protect their gold in wars whose weapons, rapidly developed by servile scientists, will become more and more deadly until they can with a flick of the finger tear a million of you to pieces RIP Craigos. A true CW legend. You will be missed.
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Quote:
 Originally Posted by Steulen dude, these are way too simple. move all X's to one side of the equation and all loose terms to the other, and bingo. for instance, the first one: 5x - 2 = x + 10 5x -x = 10 + 2 4x = 12 x = 3
Thanks, and I know these are easy but when you've been off school for months you forget things.

 23-04-2009, 07:53 AM #6 (permalink) Eternal Optimist     Join Date: Dec 2005 Location: Shake my tree where's the apple for me? Posts: 43,601 There is nothing pathetic about being stuck, or needing help, cdm
 23-04-2009, 07:53 AM #7 (permalink) Eternal Optimist     Join Date: Dec 2005 Location: Shake my tree where's the apple for me? Posts: 43,601 And it seems my method is wrong, jeez shows you how lnog it's been since I learned these things
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Instead of asking us to do the homework, you should post the question, and then show your attempt at a solution.

There are steps to solving systems of equations. List them, and try to follow them. Show your work, and then ask when you are stuck. You're not going to learn how to do it by having us do your homework.
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Quote:
 Originally Posted by Steulen dude, these are way too simple. move all X's to one side of the equation and all loose terms to the other, and bingo. for instance, the first one: 5x - 2 = x + 10 5x -x = 10 + 2 4x = 12 x = 3
I tried that on the second one I did.

5x-3x=-2+1
2x=-1
x=-0.5

Thats wrong though, what did I do wrong?

 23-04-2009, 08:00 AM #10 (permalink) International Regular     Join Date: Aug 2004 Location: Clydeside Cloggie Posts: 3,189 these are a little harder, because with two unknowns you have to balance both equations in such a way that one of the unknowns gets cancelled out. So: 5x + 3y = 8 3x - y = 9 let's first move all non-x terms to the right of the equations: 5x = 8 - 3y 3x = 9 + y then make sure both x terms are equal, by multiplying the first equation by 3,, and the second equation by 5: 15x = 24 - 9y 15x = 45 + 5y this means that 24-9y = 45+5y, as they both equal 15x. you can then do the same thing as with the earlier equation where you only has to solve X: -9y - 5y = 45 -24 -14y = 21 y = -1.5 Then substitute this value for y in any of the two original equations to find x; 5x + (3*-1.5) = 8 5x - 4.5 = 8 5x = 12.5 x = 2.5
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Quote:
 Originally Posted by cover drive man I tried that on the second one I did. 5x-3x=-2+1 2x=-1 x=-0.5 Thats wrong though, what did I do wrong?
if you move -2 to the other side, it becomes +2.

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Quote:
 Originally Posted by Steulen if you move -2 to the other side, it becomes +2.
So,

5x-3x=2+1
2x=3
x=1.5

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Quote:
 Originally Posted by cover drive man 3(x+4)=x-5 5(x-2)=2(x+4)
What about these ones, do you expand the brackets?

 23-04-2009, 08:11 AM #14 (permalink) The Wheel is Forever     Join Date: Feb 2006 Location: USA Posts: 36,507 Remember PEMDAS. Try it out, and post your attempt. We'll help you out, but you should try it first. We'll correct what you get wrong, it's the best way to learn. Last edited by silentstriker; 23-04-2009 at 08:13 AM.
 23-04-2009, 08:14 AM #15 (permalink) International Captain     Join Date: Dec 2006 Location: Liverpool, England Posts: 7,049 I got this 3(x+4)=x-5 3x+12=x-5 3x-x=-5-12 2x=-17 x=-8.5

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