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#1 (permalink) |
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International Coach
Join Date: Sep 2006
Location: Bitch please, I'm from West Yorkshire
Posts: 14,986
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Question on Standard form
In some Maths homework, I came across a slight problem when using Standard form.
The answer to a question was 29.7867*10^(-1) Becuase I know you can't have a correct Standard Form number starting with a number that is <10, so I remembered that you move the decimal place one place to the left, so that the number ended up being 2.978768*10^(???) The problem is, is that I don't know what to put the index number (or power) as, because it is near to 0. Anyone who can help? |
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#2 (permalink) |
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Cricket Web Staff Member / Global Moderator
Join Date: Mar 2002
Location: Oxford, England
Posts: 26,361
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A number x10^(-1) is a number multiplied by 0.1 - seeing as 10^(-1) = 1/(10^1) = 1/10 = 0.1
So your number is 29.7 x 0.1 = 2.97 You're right, a standard form answer must start with a number between 1 and 9.999 - so you need to adjust the second part of the SF number to reflect that. 2.97 x 10^(?) = 2.97 Clearly the answer to [10^(?)] needs to be 1 in order for the calculation to balance - and anything to the power of zero is 1. 29.7x10^(-1) = 2.97x10^0 --- Another way of looking at it is that you have divided the left-hand part of the calculation by ten, so you must multiply the right-hand part by the same amount to keep its value constant.
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#4 (permalink) |
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Eyes not spreadsheets
Join Date: Nov 2001
Location: England
Posts: 56,346
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IIRC 10^(-1) is the same as 1/10.
So the answer would be 2.97867
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#7 (permalink) |
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International Coach
Join Date: Jan 2003
Location: Midlands, UK
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To doubly complicate things, you have engineering standard form which asks for the exponential to be of the order of three i.e. milli, micro, kilo, mega, giga etc.
I'd leave it without the standard form unless it explicitly asks for it.
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#8 (permalink) |
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International Coach
Join Date: Nov 2003
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Fairly quality idea, never thought of asking fellow CWers to do my homework for me.
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#13 (permalink) | |
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State Captain
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#15 (permalink) | |
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