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Old 30-08-2005, 03:06 AM   #46 (permalink)
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Originally Posted by marc71178
And the accountants leave it to the Tax geeks...
And if I were the tax geek I would say do it yourself.
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Old 30-08-2005, 03:08 AM   #47 (permalink)
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Quote:
Originally Posted by aussie
Here is one of the most complicated things i've ever done in maths its so confusing

FH (X) = 2X - 3
X +4

Find A: H (-3)
B: H(1/2)
C: H(5)

D: Calculate the value for X if (1): H(X) = 3
(2): H(X) is undefined
I'm stumped.
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Old 30-08-2005, 04:01 AM   #48 (permalink)
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Old 30-08-2005, 04:11 AM   #49 (permalink)
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It looks pretty simple to me actually.

Just looks like substitution. The last one was a bit trickier (the unknown one) but it just involved fidding around with the equation to change the subject.
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Old 30-08-2005, 04:47 AM   #50 (permalink)
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Quote:
Originally Posted by Paid The Umpire
A ---> x = -1.8
B ---> x = 5 and a third
C ---> x = -5 and two thirds
Da ---> x = -15
Db ---> x = (3 + 4H(X)) over (2 - H(X))

I thinks...
Is this right? Cos I got totally different answers ... maybe I am on the wrong wavelength. It was hard to decipher what Aussie meant though. Too bad he's not here to clarify ...
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Old 30-08-2005, 04:58 AM   #51 (permalink)
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Originally Posted by burkey_1988
Is this right? Cos I got totally different answers ... maybe I am on the wrong wavelength. It was hard to decipher what Aussie meant though. Too bad he's not here to clarify ...
Yeah... I got -9 for the first one...
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Old 30-08-2005, 05:05 AM   #52 (permalink)
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Quote:
Originally Posted by aussie
Here is one of the most complicated things i've ever done in maths its so confusing

FH (X) = 2X - 3
X +4

Find A: H (-3)
B: H(1/2)
C: H(5)

D: Calculate the value for X if (1): H(X) = 3
(2): H(X) is undefined
My answers:

A: -9
B: -4/9
C: 7/9
D: (1) -15
(2) -4

Maths experts, am I correct?
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Old 30-08-2005, 05:21 AM   #53 (permalink)
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Woah, I have no idea what's going on.
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Old 30-08-2005, 05:23 AM   #54 (permalink)
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My answers:

A) -9
B) -4/9
C) 7/9
D) 1. -15

3. X = (3+4y)/(2-y)
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Old 30-08-2005, 05:27 AM   #55 (permalink)
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Isn't D (2) X=-4 ... to be undefined to denominator has to be zero. Therefore, when X = -4 the denominator is zero
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Old 30-08-2005, 05:40 AM   #56 (permalink)
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Quote:
Originally Posted by twctopcat
I did Econometric Methods in the second year, taught by Cherif Guermat, what a man!! Never really worked out the difference between the 2 but i know they should be worth double most other modules. Brilliant stuff with the 77 though, your a better man than me! You on for a first then??
Yep - 75 in Macro and 100 in Micro (and 61 in French) - average of 78.25 and well on for a good first
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Old 30-08-2005, 06:17 AM   #57 (permalink)
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how long is aussie banned for ?
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Old 30-08-2005, 06:30 AM   #58 (permalink)
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Quote:
Originally Posted by Neil Pickup
Yep - 75 in Macro and 100 in Micro (and 61 in French) - average of 78.25 and well on for a good first
100 in micro, my mate got in the 90's and i thought he was good! Fair play!
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Old 30-08-2005, 11:07 AM   #59 (permalink)
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Quote:
Originally Posted by Craig
And if I were the tax geek I would say do it yourself.
No, the tax geeks actually enjoy it!
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Old 30-08-2005, 11:38 AM   #60 (permalink)
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I can confirm that Burkey is right on all counts.

Basically what it means is:
To calculate H given a set value of X, just do: (2x-3)/(x+4)

If X=-3, then H=(-9)/(1) = -9
If X=0.5, then H=(-2)/(-4.5) = -0.44 or -4/9
If X=5, then H=(7)/(9) = 0.78 or 7/9

For the next part, you need (2x-3)/(x+4) to equal three.
Multiplying both sides by (x+4) gives you (2x-3) = 3(x+4)
Expansion gives 2x-3 = 3x+12
Collecting like terms gives you x=-15

The last part is the easiest. For a fraction to be undefined, the bottom (denominator) has to be zero. So... (x+4) = 0 - and x = -4
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