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#46 (permalink) | |
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World Traveller
Join Date: May 2003
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Quote:
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#47 (permalink) | |
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World Traveller
Join Date: May 2003
Location: Super Happy Fun Sugar Lollipop Land!
Posts: 34,131
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#48 (permalink) |
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All Time Legend
Join Date: Mar 2002
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Thanks. I am great!
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JOIN the CRICKETWEB.NET STEAM GROUP |
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#49 (permalink) |
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Global Moderator
Join Date: Jul 2003
Location: New South Wales
Posts: 37,731
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It looks pretty simple to me actually.
Just looks like substitution. The last one was a bit trickier (the unknown one) but it just involved fidding around with the equation to change the subject.
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#50 (permalink) | |
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Cricketer Of The Year
Join Date: Jan 2005
Location: Sydney
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#51 (permalink) | |
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Global Moderator
Join Date: Jul 2003
Location: New South Wales
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#52 (permalink) | |
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Cricketer Of The Year
Join Date: Jan 2005
Location: Sydney
Posts: 7,584
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Quote:
A: -9 B: -4/9 C: 7/9 D: (1) -15 (2) -4 Maths experts, am I correct? |
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#54 (permalink) |
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International Regular
Join Date: Jan 2004
Location: winchester, england
Posts: 3,477
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My answers:
A) -9 B) -4/9 C) 7/9 D) 1. -15 3. X = (3+4y)/(2-y)
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R.I.P Fardin Qayyumi (Cricket Player) 'Last one on drugs is a queer,' yells portillo.. Hope is a good thing, maybe even the best of things. And no good thing ever dies...... Self appointed president of the KPPAS |
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#56 (permalink) | |
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Cricket Web Staff Member / Global Moderator
Join Date: Mar 2002
Location: Oxford, England
Posts: 26,361
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Quote:
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MSN Messenger: minardineil2000 at hotmail dot com | AAAS Chairman CricketWeb Black | CricketWeb XI Captain ClarkeWatch: We're Watching Rikki - Are You? Up The Grecians - Exeter City FC Completing the Square: My Cricket Web Blog |
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#58 (permalink) | |
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International Regular
Join Date: Jan 2004
Location: winchester, england
Posts: 3,477
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#59 (permalink) | |
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Eyes not spreadsheets
Join Date: Nov 2001
Location: England
Posts: 56,346
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Quote:
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marc71178 - President and founding member of AAAS - we don't only appreciate when he does well, but also when he's not quite so good! Anyone want to join the Society? Beware the evils of Kit-Kats - they're immoral apparently. |
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#60 (permalink) |
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Cricket Web Staff Member / Global Moderator
Join Date: Mar 2002
Location: Oxford, England
Posts: 26,361
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I can confirm that Burkey is right on all counts.
Basically what it means is: To calculate H given a set value of X, just do: (2x-3)/(x+4) If X=-3, then H=(-9)/(1) = -9 If X=0.5, then H=(-2)/(-4.5) = -0.44 or -4/9 If X=5, then H=(7)/(9) = 0.78 or 7/9 For the next part, you need (2x-3)/(x+4) to equal three. Multiplying both sides by (x+4) gives you (2x-3) = 3(x+4) Expansion gives 2x-3 = 3x+12 Collecting like terms gives you x=-15 The last part is the easiest. For a fraction to be undefined, the bottom (denominator) has to be zero. So... (x+4) = 0 - and x = -4 |
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